Answer:
[tex]CD=6.51\ cm[/tex]
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional
In this problem Triangles ABE and CDE are similar by AA Similarity Theorem
so
[tex]\frac{AE}{CE}=\frac{AB}{CD}[/tex]
step 1
Find the value of AE
Applying the Pythagorean Theorem in the right triangle ABE
[tex]BE^2=AB^2+AE^2[/tex]
[tex]16^2=7^2+AE^2[/tex]
[tex]256=49+AE^2[/tex]
[tex]AE^2=256-49[/tex]
[tex]AE^2=207[/tex]
[tex]AE=\sqrt{207}\ cm[/tex]
step 2
Find the value of CD
[tex]\frac{AE}{CE}=\frac{AB}{CD}[/tex]
substitute the given values
[tex]\frac{\sqrt{207}}{\sqrt{207}-1}=\frac{7}{CD}[/tex]
[tex]CD=(7)\frac{\sqrt{207}-1}{\sqrt{207}}[/tex]
[tex]CD=6.51\ cm[/tex]