Respuesta :
Answer:
mass of ice = 92.2 g
Explanation:
[tex]density=\frac{mass}{volume}[/tex]
Volume given = 352 mL
Density of water = 1.0 g/mL
Mass = density × volume
= 1.0 g/mL × 352 mL
= 352 g
[tex]q=m\times c\times \Delta t[/tex]
Where,
q = heat given or taken
c = specific heat capacity
Δt = change in temperature
Specific heat capacity = 4.18 J/g°C
First calculate the heat given by water by lowering temperature:
[tex]q=m\times c\times \Delta t\\=352\times 4.18 \times (4-26)\\=-32369.9\ J[/tex]
Heat given by water will be utilized in melting ice.
[tex]q_{ice}=-q_{water}[/tex]
[tex]q_{ice}=n\Delta H_{fus}+m\times c\times \Delta t[/tex]
ΔH(fus)=6020 J/mol
[tex]q_{ice}=n\Delta H_{fus}+m\times c\times \Delta t\\=\frac{m_{ice}}{18} mol \times 6020\ J/mol+m_{ice} \times 4.18 \times (4-0)\\m_{ice}(\frac{1}{18} mol \times 6020\ J/mol+ 4.18 \times (4-0))\\=q_{ice}=-q_{water}\\m_{ice}(334.26+16.72)=-(-32369.9)\\m_{ice}350.98=32369.9\\m_{ice}=92.2\ g)[/tex]
Mass of ice = 92.2 g
Given:
Volume given = 352 mL
Density of water = 1.0 g/mL
Density:
It is defined as the ratio of mass over volume.
[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}}\\\\\text{Mass}=\text{Density}*\text{Volume}\\\\\text{Mass}=1.0g/mL*352mL\\\\\text{Mass}=352g[/tex]
From, specific heat formula:
The specific heat capacity of a substance is the heat capacity of a sample of the substance divided by the mass of the sample.
Where,
q=m*C*ΔT
q = heat given or taken
C = specific heat capacity
ΔT = change in temperature
Specific heat capacity = 4.18 J/g°C
On substituting the values:
First calculate the heat given by water by lowering temperature:
[tex]q=m*C*\triangle T\\\\q=352*4.18*(4-26)\\\\q=-32369.9J[/tex]
Heat given by water will be utilized in melting ice:
[tex]q_{ice}=-q_{water}\\\\q_{ice}=n\triangle H_{fus}+m*C*\triangle T\\\\H_{fus}=6020J/mol\\\\q_{ice}=n\triangle H_{fus}+m*C*\triangle T\\\\q_{ice}=\frac{m_{ice}}{18}mol*6020J/mol+m_{ice}*4.18*(4-0)\\\\q_{ice}=m_{ice}(\frac{1}{18} *6020J/mol+m_{ice}*4.18*(4-0))\\\\q_{ice}=-q_{water}\\\\m_{ice}*(334.26+16.72)=-(-32369.9)\\\\m_{ice}*(350.98)=32369.9\\\\m_{ice}=92.2g[/tex]
Thus, mass of ice that is required to lower the temperature will be 92.2 grams.
Find more information about "Density" here:
brainly.com/question/13439286
