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What is the value of h when the function is converted to vertex form? Note: Vertex form is f(x)=a(x−h^)2+k . f(x)=x^2+10x+35

Respuesta :

apologiabiology
hack: the x value of the vertex (or h) can be found directily from f(x)=ax²+bx+c

so

for f(x)=ax²+bx+c, [tex]h= \frac{-b}{2a} [/tex]
so
given

f(x)=1x²+10x+35, [tex]h= \frac{-10}{2(1)} [/tex]=-5

h=-5

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