Respuesta :
Answer:
The dimensions of rectangle are width is 2 and the length is 4.
Step-by-step explanation:
Given:
The perimeter of a rectangle is 12. The length is 2 more than the width.
Now, to find both the dimensions.
Let the width be [tex]x[/tex].
And the length be [tex]2+x[/tex].
Now, putting the formula to get the dimensions:
Perimeter = 2(length + width)
[tex]12=2((2+x)+x)[/tex]
⇒[tex]12=4+2x+2x[/tex]
⇒[tex]12=4+4x[/tex]
Subtracting both sides by 4 we get:
⇒[tex]8=4x[/tex]
Dividing both sides by 4 we get:
⇒[tex]2=x[/tex]
So, the width = 2.
And the length = 2+2=4.
Therefore, the dimensions of rectangle are width is 2 and the length is 4.
Answer:
The dimensions of rectangle as , Length is 4 unit and width is 2 unit
Step-by-step explanation:
Given as :
The Perimeter of Rectangle = 12 unit
The length is 2 more than the width
Let The Length of Rectangle = L unit
And The width of Rectangle = w unit
According to question
Length = 2 + width
I.e L = 2 + w ...............1
Now, From The Perimeter of Rectangle
Perimeter = 2 × Length + 2 × width
Or, Perimeter = 2 × L + 2 × w
Or, 12 unit = 2 × (2 + w) + 2 × w
Or, 12 = 4 + 2 w + 2 w
or, 12 - 4 = 4 w
Or, 8 = 4 w
∴ w = [tex]\frac{8}{4}[/tex]
I.e w = 2 unit
So, The width of Rectangle = w = 2 unit
Put The value of w in Eq 1
So, L = 2 + w
I.e L = 2 + 2
∴ L = 4 unit
So, The length of Rectangle = L = 4 unit
Hence The dimensions of rectangle as , Length is 4 unit and width is 2 unit Answer
