Respuesta :
The general form for a geometric series is:
an = a1 r^(n-1)
with a1 as 1.5
and r = 0.71
So,
a.
The rule for sequence is:
an = 1.5 (0.71)^(n - 1)
b.
After the sixth path, the height of the ball at the top is
a6 = 1.5 (0.71)^(6 - 1)
a6 = 0.27 m
an = a1 r^(n-1)
with a1 as 1.5
and r = 0.71
So,
a.
The rule for sequence is:
an = 1.5 (0.71)^(n - 1)
b.
After the sixth path, the height of the ball at the top is
a6 = 1.5 (0.71)^(6 - 1)
a6 = 0.27 m
a. write a rule for the sequence using centimeters. The initial height is given by term n = 1
For this case we have a sequence of the form:
[tex] an = a0 * (r) ^ {(n-1)}
[/tex]
Where
a0: initial height
r: rate of change
n: number of paths
On the other hand we have the following conversion:
1 meter = 100 centimeters
Therefore we have:
[tex] (1.5) * (100) = 150 cm
[/tex]
Thus, the general rule for the sequence in centimeters is:
[tex] an = 150 * (0.71) ^ {(n-1)}
[/tex]
Answer:
a rule for the sequence using centimeters is:
[tex] an = 150 * (0.71) ^ {(n-1)}
[/tex]
b. what height will the ball be at the top of the sixth path
For this case, we substitute the value of n = 6 in the equation obtained in part a.
We have then:
[tex] a6 = 150 * (0.71) ^ {(6-1)}
a6 = 27.06 cm
[/tex]
Answer:
the height of the ball will be 27.06 at the top of the sixth path