Answer:
The probability that more than half of the sample would vote for him is P=0.7549.
Step-by-step explanation:
With a sample size of n=300, we can approximate this to the normal distribution.
The parameters will be
[tex]\mu=p\cdot n=0.52\cdot 300=156\\\\\sigma=\sqrt{np(1-p)} =\sqrt{300\cdot 0.52(1-0.52)} =\sqrt{74.88}= 8.65[/tex]
We have to calculate the probability that half or more of the sample vote for him. This is P(x>150).
To calculate this probability, first we calculate the z-value:
[tex]z=\frac{x-\mu}{\sigma}=\frac{150-156}{8.65}=\frac{-6}{8.65}=-0.69[/tex]
Then
[tex]P(x>150)=P(z>-0.69)=0.7549[/tex]
The probability that more than half of the sample would vote for him is P=0.7549.