Respuesta :
Answer:
2.41 × 10^23 formula units
Explanation:
The equation for the reaction is;
2 Na(NO₃) + Ca(CO₃) → Na₂(CO₃) + Ca(NO₃)₂
We are given;
Mass of calcium carbonate as 20.0 g
We need to determine the number of formula units of sodium nitrate that will react with 20 g of calcium carbonate.
Step 1: Calculate the number of moles of Calcium carbonate
To calculate the number of moles we divide mass by the molar mass;
Number of moles = Mass ÷ Molar mass
Molar mass of CaCO₃ = 100.087 g/mol
Number of moles = 20 g ÷ 100.087 g/mol
= 0.20 moles
Step 2: Moles of Sodium nitrate that reacted
From the equation, 2 moles of NaNO₃ reacts with 1 mole of CaCO₃
Thus, the mole ratio of NaNO₃ to CaCO₃ is 2 : 1
Therefore; Number of moles of NaNO₃ = Moles of CaCO₃ × 2
= 0.20 moles × 2
= 0.40 moles
Step 3: Calculate formula units of NaNO₃
We need to know that 1 mole of a compound contains formula units equivalent to the Avogadro's constant.
That is; 1 mole of a compound contains 6.022 × 10^23 formula units
Therefore; 0.4 moles of NaNO₃ will have;
= 0.4 moles × 6.022 × 10^23 formula units
= 2.4088 × 10^23 formula units
= 2.41 × 10^23 formula units
Therefore, the number of formula units of sodium nitrate required will be 2.41 × 10^23 formula units
The study of chemicals and bonds is called chemistry. The reaction is a displacement reaction, in this type of reaction, one element displaces the other.
The correct answer is[tex]2.41 * 10^{23}[/tex]formula units
The equation for the following question is as follows:-
[tex]2 Na(NO_3) + Ca(CO_3) ---> Na_2(CO_3) + Ca(NO_3)_2[/tex]
Moles:-
- The mole is the base unit of amount of substance in the International System of Units.
- It is defined as exactly 6.02214076×10²³ elementary entities, which may be atoms, molecules, ions, or electrons. Wikipedia
The data is given in the question is as follows:-
- Mass of calcium carbonate as 20.0 g
We have to find the number of formula units of sodium nitrate that will react with 20 g of calcium carbonate.
The formula is used to solve the question.
[tex]Number\ of\ moles = \frac{Mass} { Molar mass}[/tex]
- Molar mass of CaCO₃ = 100.087 g/mol
Number of moles = [tex]\frac{20} {100.087}[/tex]
= 0.20 moles
From the equation, 2 moles of [tex]NaNO_3[/tex] reacts with 1 mole of [tex]CaCO_3[/tex] Thus, the mole ratio of[tex]NaNO_3 to CaCO_3[/tex]2 : 1
Therefore; the Number of moles of NaNO₃ =
[tex]Moles of CaCO_3* 2\\= 0.20 moles * 2\\= 0.40 moles[/tex]
1 mole of a compound contains [tex]6.022 *10^{23}[/tex] NaNO₃ will have:-
[tex]0.4 moles * 6.022 * 10^{23} formula\ units= 2.4088 * 10^{23} formula \ units= 2.41 * 10^{23} formula\ units[/tex]
Hence, the correct answer is [tex]2.41 * 10^{23}[/tex]formula units.
For more information about the question, refer to the link:-
https://brainly.com/question/491373
