Count the distance d, which gives you 7.
Use Pythogarean theorem to find c:
[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]
Plug in the numbers:
[tex] {4}^{2} + {3}^{2} = {c}^{2} \\ \\ = 16 + 9 \\ \\ = 25 \\ \\ c = \sqrt{25} = 5[/tex]
c is 5.
Same thing with g:
[tex] {e}^{2} + {f}^{2} = {g}^{2} \\ \\ {g}^{2} = {4}^{2} + {4}^{2} \\ \\ = 16 + 16 \\ \\ = 32 \\ \\ g = \sqrt{32} = 4 \sqrt{2} = 5.66[/tex]
g equals 5.66.
