Answer:
The equation of line in point slop from is
y - 8 = -[tex]\frac{2}{3}[/tex] × (x + 3 )
Step-by-step explanation:
Given slop-intercept line equation as :
y = -[tex]\frac{2}{3}[/tex]x + 6
I.e y = mx + c
and point the line is passing through ( -3 , 8 )
So, point slop form of this line is
y - y_1 = m × (x - x_1)
Slop of above line is - [tex]\frac{2}{3}[/tex]
Now line passes through given points and this slop is
y - 8 = - [tex]\frac{2}{3}[/tex] × (x + 3 )
Hence the equation of line in point slop from is
y - 8 = - [tex]\frac{2}{3}[/tex] × (x + 3 ) Answer
