Answer:
67200
Step-by-step explanation:
We are given that the access code for a car's security system consist of six digits.
First digit cannot be zero and the last digit must be odd.
We have available digits which can used from 0 to 9.
We have to find the number of different codes are available without replacement.
Total odd digits=1,3,5,7,9=5
The sixth place place can be filled by number of ways=5
The first place can be filled by number of ways=8
The second place filled by number of ways=8
The third place can be filled by number of ways=7
The fourth place can be filled by number of ways=6
The fifth place can be filled by number of ways=5
Therefore, the total number of different codes are available=[tex]5\times 8\times 8\times 7\times 6\times 5=67200[/tex]
Answer:67200
