Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water.

In a chemical reaction, the structure of atoms as chemical elements is unchanged. Atoms in one element do not become atoms in another element. There is also no loss or creation of new atoms. The number of atoms of the reagents must be equal to the number of atoms of the products. When this happens, we say that the chemical equation is balanced.

For this reason, we can state that the balanced chemical reaction where solid iron (III) oxide reacts with hydrogen gas to form solid iron and liquid water would be:

Fe2O3 + 3 H2 = 2 Fe + 3 H2O

dsdrajlin dsdrajlin · Answer 2 · 2021-09-04T00:37:51+02:00

I think this is the complete question:

Write the balanced chemical equation for the following reaction. Phases are optional.

Solid iron (III) oxide reacts with hydrogen gas to form solid iron and liquid water.

The balanced chemical equation for the reaction between solid iron (III) oxide and hydrogen gas to form solid iron and liquid water is:

Fe₂O₃(s) + 3 H₂(g) ⇒ 2 Fe(s) + 3 H₂O(l)

Let's consider the unbalanced equation that occurs when solid iron (III) oxide reacts with hydrogen gas to form solid iron and liquid water. This is a redox reaction.

Fe₂O₃(s) + H₂(g) ⇒ Fe(s) + H₂O(l)

We can balance it using the trial and error method. First, we will balance O atoms by multiplying H₂O by 3.

Fe₂O₃(s) + H₂(g) ⇒ Fe(s) + 3 H₂O(l)

Then, we balance H atoms by multiplying H₂ by 3.

Fe₂O₃(s) + 3 H₂(g) ⇒ Fe(s) + 3 H₂O(l)

Finally, we get the balanced equation by multiplying Fe by 2.

Fe₂O₃(s) + 3 H₂(g) ⇒ 2 Fe(s) + 3 H₂O(l)

The balanced chemical equation for the reaction between solid iron (III) oxide and hydrogen gas to form solid iron and liquid water is:

Fe₂O₃(s) + 3 H₂(g) ⇒ 2 Fe(s) + 3 H₂O(l)

You can learn more about balancing chemical equations here: https://brainly.com/question/7181548