A person pushes horizontally on a heavy box and slides it across the level floor at constant velocity. The person pushes with a 60.0 N force for the first 7.09 m, at which time he begins to tire. The force he exerts then starts to decrease linearly from 60.0 N to 0.00 N across the remaining 7.09 m. How much total work did the person do on the box?

Respuesta :

Answer:

W= 638.1 J

Explanation:

As we know that

Work done is the area of the force and displacement diagram.

W=∫F.dx

W=Work

F=force

dx=Elemental displacement

From the diagram ,area A

A= 60 x 7.09 + 1/2 x 60 x 7.09

A= 638.1 J

So the work W

W= 638.1 J

Ver imagen Netta00

To solve the problem we must know about the concept of Work done.

What is work done?

Work done can be defined as the product of force that is been applied and the displacement that is been caused due to this force.

[tex]W = \int Fdx[/tex]

The work done by the man is equal to 631.8 J.

Given to us

The force that is been applied on the box for the first 7.09 m is 60 N,

The force that is been applied on the next 7.09 m is decreasing linearly from 60.0 N to 0.00 N

We know about the concept of work done, Now let's draw a graph based on the information that is been given to us,

[tex]W = \int Fdx[/tex]

We also, know that area under the graph shows us the amount of work that is been done,

[tex]W = \text{Area in the rectange } + \text{Area in the triangle}\\[/tex]

W = (60 x 7.09) + (0.5 x 60 x 7.09)

W = 638.1 J

Hence, the work done by the man is equal to 631.8 J.

Learn more about Work Done:

https://brainly.com/question/3902440

Ver imagen ap8997154