a student is running an experiment in which 42.0 grams of coso4 is needed, but the only jar of reagent in the lab is labelled cobalt(ii) sulfate hexahydrate. how many grams of the hydrate must the student weigh out in order to get the desired amount of the anhydrous compound?

Respuesta :

A mass of 71.26g of [tex]CoSO_4.6H_2O[/tex] is required to get 42g of the anhydrous compound, i.e., [tex]CoSO_4[/tex].

A compound's molar mass indicates the mass of one mole of that substance. In other words, it informs you how many grams of a substance there are per mole. A covalent compound's formula mass is also known as its molecular mass. The mole is a useful quantity unit for representing very large quantities of atoms or molecules. A substance's molecular mass is the total of the atomic masses of all the atoms that comprise the molecule of the substance.

The term anhydrous means "without water." Anhydrous chemicals are compounds that do not contain water or do not contain water. An anhydrate is formed when water is removed from a hydrate. Suction or high-temperature heating of the chemical removes the water molecules. An anhydrous salt, for example, has had water driven out of its crystals.

Given:

Mass of [tex]CoSO_4[/tex] needed = 42g

To find:

Mass of [tex]CoSO_4.6H_2O[/tex] = ?

Formula:

Mass of [tex]CoSO_4.6H_2O[/tex] = (Mol. Wt. of [tex]CoSO_4.6H_2O[/tex] / Mol. Wt. of [tex]CoSO_4[/tex]) x Mass of [tex]CoSO_4[/tex]

Calculations:

Mol. Wt. of [tex]CoSO_4[/tex] = 155g/mol

Mol. Wt. of [tex]CoSO_4.6H_2O[/tex] = 155 + 6 x 18 = 263g/mol

Mass of [tex]CoSO_4.6H_2O[/tex] = (263 / 155) x 42

Mass of [tex]CoSO_4.6H_2O[/tex] = 71.26g

Result:

71.26g of [tex]CoSO_4.6H_2O[/tex] is required to get 42g of the anhydrous compound.

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