The true statement about the CD is:
b. No net torque acts on it at all.
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Further explanation
Centripetal Acceleration can be formulated as follows:
[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]
a = Centripetal Acceleration ( m/s² )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
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Centripetal Force can be formulated as follows:
[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]
F = Centripetal Force ( m/s² )
m = mass of Particle ( kg )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
Let us now tackle the problem !
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Complete Question:
A CD spins at a constant angular velocity of 5.0 revolutions per second clockwise. Which of the following statements about the CD is true?
a. A net torque acts on it clockwise to keep it moving
b. No net torque acts on it at all.
c. A net torque acts on it counterclockwise to keep it moving
Given:
angular velocity = ω = 5.0 revolutions per second
Asked:
net torque = Στ = ?
Solution:
Constant angular velocity → angular acceleration = α = 0 rad/s²
[tex]\Sigma \tau = I \alpha[/tex]
[tex]\Sigma \tau = I (0)[/tex]
[tex]\Sigma \tau = 0 \texttt{ Nm}[/tex]
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Conclusion:
The true statement about the CD is:
b. No net torque acts on it at all.
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Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
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Answer details
Grade: High School
Subject: Physics
Chapter: Circular Motion
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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
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