contestada


please help me omg

What is the equation of the line perpendicular to the line
y = 2/3x + 2 that passes through the point (1,5)?
a. y = -1/4x + 2
b. y = 1/4x + 2
c. y = 4x + 2
d. y =-4x + 2

Respuesta :

kakakazada
The perpendicular slope is the (-1/original slope) so the perpendicular slope would be (-1/(2/3)) = -3/2
Then plug in the point (1,5) into a new y=mx+b with the perpendicular slope and solve for b
5 = (1)(-3/2) + b
b = 13/2
So the new equation is y = (-3/2)x + (13/2)
I think the answer choices are wrong

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