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A 0.76 kg ball moves in a circle that is 0.8 m in radius at a speed of 4.3 m/s. Calculate
the centripetal acceleration of the ball.

Respuesta :

26clycan

Answer:

The centripetal acceleration of the ball can be calculated using the formula:

a = v^2 / r

where

v = 4.3 m/s (speed of the ball)

r = 0.8 m (radius of the circle)

Plugging in the values:

a = (4.3 m/s)^2 / 0.8 m

a = 23.035 m/s^2

Therefore, the centripetal acceleration of the ball is 23.035 m/s^2.

ujalakhan18

Answer:

[tex]\huge\boxed{\sf a_c \approx 23.1 \ m/s^2}[/tex]

Explanation:

Given data:

Mass = m = 0.76 kg

Radius = r = 0.8 m

Speed = v = 4.3 m/s

Required:

Centripetal acceleration = [tex]a_c[/tex] = ?

Formula:

[tex]\displaystyle a_c=\frac{v^2}{r}[/tex]

Solution:

Put the given data in the above formula.

[tex]\displaystyle a_c=\frac{(4.3)^2}{0.8} \\\\\displaystyle a_c=\frac{18.49}{0.8} \\\\a_c \approx 23.1 \ m/s^2\\\\\rule[225]{225}{2}[/tex]

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