In a spacecraft, this reaction occurs:

CO2(g)+2LiOH(s)→LiCO3(s)+H2O(l)

How many liters of carbon dioxide will 3 moles of lithium hydroxide (LiOH) absorb?

(One mole of any gas occupies 22.4 L under certain conditions of temperature and pressure. Assume those conditions for this question.)

6.0 L


20 L

3.0 L


34 L

Respuesta :

Volume of carbon dioxide absorbed = 33.6 L ≈ 34 L

Explanation:

We have the following chemical reaction:

CO₂ (g) + 2 LiOH (s) → Li₂CO₃ (s) + H₂O (l)

Now we devise the following reasoning:

if        1 mole of carbon dioxide reacts with 2 moles of lithium hydroxide

then   X moles of carbon dioxide reacts with 3 moles of lithium hydroxide

X = (1 × 3) / 2 = 3/2 moles of carbon dioxide

And we calculate the volume of carbon dioxide using the following formula:

number of moles = volume / 22.4

volume = number of moles × 22.4

note: units for 22.4 are "L / mole"

volume of carbon dioxide = (3/2) × 22.4 = 33.6 L ≈ 34 L

Learn more about the reaction of carbon dioxide with metal hydroxides:

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Answer:

I can confirm that it is 34 L no question asked its correct

Explanation: