Answer:
102.92 feet
Step-by-step explanation:
x is the horizontal distance [what we want to find]
f(x) represents the vertical height
Since, we want the horizontal distance traveled [x] before hitting ground [vertical height is 0, so f(x) = 0]
We want:
[tex]f(x)=-0.01x^2+x+3[/tex]
We will use quadratic formula to solve this. Quadratic Formula is:
[tex]x=\frac{-b+-\sqrt{b^2 -4ac} }{2a}[/tex]
Where a is coefficient of x^2 and b is coefficient of x and c is the constant
Now, let's solve:
[tex]x=\frac{-b+-\sqrt{b^2 -4ac} }{2a}\\x=\frac{-1+-\sqrt{(1)^2 -4(-0.01)(3)} }{2(-0.01)}\\x=102.92,-2.92[/tex]
We disregard the negative solution [no neg distance] and take 102.92 feet as our answer
