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A 66.5-kg hiker starts at an elevation of 1270 m and climbs to the top of a peak 2660 m high.
(a) What is the hiker?s change in potential energy?
(b) What is the minimum work required of the hiker?
(c) Can the actual work done be greater than this? Explain.

Respuesta :

Answer

given,

mass of the hiker = 66.5 kg

elevation of the hiker,h₁ = 1270 m

elevation of top peak,h₂ = 2660 m

a) Change in potential energy

    Δ PE = m g h₂ - m g h₁

    Δ PE = m g (h₂ - h₁)

    Δ PE = 66.5 x 9.8 x  (2660 - 1270)

    Δ PE = 905863 J

b) Minimum work require by the hiker will be equal to Δ PE = 905863 J

c) yes, it can be more than this, if friction is present on the surface.

   

Cricetus

(a) Change in P.E is "905863 J".

(b) Min work required is "905863 J".

(c) Yes, the actual work done can be more than this.

Given values are:

  • Mass, [tex]m = 66.5 \ kg[/tex]
  • Elevation of hiker, [tex]h_1 = 1270 \ m[/tex]
  • Top elevation, [tex]h_2 = 2660 \ m[/tex]

(a)

As we know,

→ [tex]\Delta PE = mgh_2 -mgh_1[/tex]

or,

            [tex]= mg(h_2-h_1)[/tex]

By substituting the values, we get

            [tex]= 66.5\times 9.8(2660-1270)[/tex]

            [tex]= 905863 \ J[/tex]

(b)

→ Min work require = Change in P.E

i.e., "905863 J"

(c)

  • If the friction is present on the surface of the floor, then the work done will be greater.

Thus the responses above are correct.

Learn more about P.E here:

https://brainly.com/question/17250193

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