Answer:
The actual yield of iron = 0.294 moles
Explanation:
Step 1: The balanced reaction
Fe2O3 +3C → 2Fe + 3CO
For 1 mole of Fe2O3 consumed, there is needed 3moles of Carbon to produce 2 moles of Fe and 3 moles of CO
Step 2: Calculate moles of Fe
Moles of iron = mass of iron / Molar mass of iron
moles of iron = 16.4 g / 55.845g/mole = 0.294 mole
The actual yield of iron = 0.294 mole
Step 3: Fe2O3 is the limiting reactant, this means the 0.236 moles will completely react.
1 mole of Fe2O3 consumed, will produce 2 moles of Fe
This means 0.236 moles of Fe2O3 will produce 2*0.236 = 0.472 moles of Fe. This is the theoretical yield of iron.
The percentage yield = 0.294/0.472 * 100% = 62.29 %
The actual yield of iron = 0.294 moles
