Answer:
672N
Explanation:
The steel can be modeled in a certain range of applied force as an elastic element, by which we can use the following equation, which is originally from the hooke law that indicates that all material tends to recover its original form after the application of a force
[tex]F=\frac{(L1-L2)(E)(A)}{L1}\\[/tex]
where
E=young modulos=200.000Mpa
A= Cross-sectional area
=[tex]\frac{\pi }{4} d^2=\frac{\pi }{4} (0.85mm)^2=0.567mm^2[/tex]
L1=leght=1.35m=1350mm
L1-L2= deformation=8mm
solving
[tex]F=\frac{(8)(200000)(0.567)}{1350}=672N[/tex]
