Answer:
The diameter is 0.378 ft.
Explanation:
Given that,
Mass of shot = 12 lb
Density of fresh water = 62.4 lb/ft
Specific gravity = 6.8
We need to calculate the volume of shot
[tex]V = \dfrac{4}{3}\pi r^3\ ft^3[/tex]
The density of shot is
Using formula of density
[tex]\rho = \dfrac{m}{V}[/tex]
Put the value into the formula
[tex]\rho =\dfrac{12}{ \dfrac{4}{3}\pi r^3}[/tex]
We need to calculate the radius
Using formula of specific gravity
[tex]specific\ gravity =\dfrac{density\ of\ shot}{dnsity\ of\ water}[/tex]
Put the value into the formula
[tex]6.8=\dfrac{\dfrac{12}{\dfrac{4}{3}\pi r^3}}{62.4}[/tex]
[tex]r^3=\dfrac{12}{\dfrac{4}{3}\pi\times6.8\times62.4}[/tex]
[tex]r^3=0.0067514[/tex]
[tex]r =(0.0067514)^{\frac{1}{3}}[/tex]
[tex]r=0.1890\ ft[/tex]
The diameter will be
[tex]d = 2\times r[/tex]
[tex]d =2\times0.1890[/tex]
[tex]d =0.378\ ft[/tex]
Hence, The diameter is 0.378 ft.
