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A system does 591 kJ of work and loses 256 kJ of heat to the surroundings.
What is the change in internal energy, AE, of the system? Note that internal energy is symbolized as AU in some sources.

Respuesta :

Answer:

-847kj

Explanation:

Delta E= -256+-591

onyebuchinnaji

The change in the internal energy of the system is -850 J.

The given parameters;

  • work done by the system, W = 591 kJ
  • heat lost to surrounding, Q = 256 kJ

The change in the internal energy of the system is determined by applying the first law of thermodynamics as shown below;

ΔU = Q - W

where;

  • Q is the heat added to the system
  • W is the work done on the surrounding by the system

ΔU = (-259) - 591

ΔU = - 850 J

Thus, the change in the internal energy of the system is -850 J.

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