Answer:
work done is = 0
Explanation:
given data
distance = 2 cm
potential = 1 V
charge with magnitude = 1 nC
to find out
work done by the electrostatic force
solution
we know that at equipotential surface is that surface which have equal potential at each every point that we say
work done will be
work done = ∫dw
∫dw = [tex]\int\limits^v1_v2 {q} \, dv[/tex]
here q is charge
so
net work done = q ( v2 - v1 )
and
so v2 = v1 = 0
so
work done is = 0
