Answer:
There are 1.041×10²³ atoms in 4.20g of Magnesium.
Explanation:
To find the amount of atoms in 4.20 g of Magnesium we need de molar mass of Mg: 24.305 g/mol
According to Avogadro number there are 6.022×10²³ particles in 1 mol, so the number of atoms of Mg is:
[tex]4.20 g Mg*\frac{1 molMg}{24.305gMg} *\frac{6.022*10^{23}atoms }{1 mol Mg} = 1.041*10^{23}atoms Mg[/tex]
Answer: The number of atoms found in given amount of magnesium is [tex]1.042\times 10^{23}[/tex]
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of magnesium = 4.20 g
Molar mass of magnesium = 24.31 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of magnesium}=\frac{4.20g}{24.31g/mol}=0.173mol[/tex]
According to mole concept:
1 mole of an element contains [tex]6.022\times 10^{23}[/tex] number of atoms
So, 0.173 moles of an element contains = [tex]0.173\times 6.022\times 10^{23}=1.042\times 10^{23}[/tex] number of atoms
Hence, the number of atoms found in given amount of magnesium is [tex]1.042\times 10^{23}[/tex]
