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How many liters of 0.1107 M KCI contain 15.00 g of KCI (FW 74.6 g/mol)? 0.02227 L O 0.5502 L 1.661 L O 1816 L 18.16 L ent Navigator PrtScr Delete FB F9 F10 F11 F12 Insert Backspace 6 U P

Respuesta :

Answer: The volume of solution required is 1.816 L

Explanation:

To calculate the molarity of solution, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]

We are given:

Mass of solute (KCl) = 15.00 g

Molar mass of potassium chloride = 74.6 g/mol

Molarity of solution = 0.1107 M

Putting values in above equation, we get:

[tex]0.1107M=\frac{15.00g}{74.6g/mol\times \text{Volume of solution}}\\\\\text{Volume of solution}=1.82L[/tex]

Hence, the volume of solution required is 1.816 L

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