Respuesta :
Answer: 14.2 grams
Explanation:-
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
given mass of phosphorous (P) = 3.07 g
Molar mass of phosphorous (P) = 31 g/mol
Putting in the values we get:
[tex]\text{Number of moles of phosphorous}=\frac{3.07g}{31g/mol}=0.1moles[/tex]
given mass of oxygen [tex]O_2[/tex] = 6.09 g
Molar mass of oxygen [tex]O_2[/tex] = 32 g/mol
Putting in the values we get:
[tex]\text{Number of moles of oxygen}=\frac{6.09g}{32g/mol}=0.2moles[/tex]
According to stoichiometry:
[tex]4P+5O_2\rightarrow 2P_2O_5[/tex]
4 moles of phosphorous combine with 5 moles of oxygen
Thus 0.1 moles of phosphorous combine with =[tex]\frac{5}{4}\times 0.1=0.125[/tex] moles of oxygen
Thus phosphorous acts as limiting reagent as it limits the formation of product and oxygen is the excess reagent.
4 moles of phosphorous gives= 2 moles of [tex]P_2O_5[/tex]
Thus 0.1 moles of phosphorous gives =[tex]\frac{2}{4}\times 0.1=0.05[/tex] moles of [tex]P_2O_5[/tex]
mass of [tex]P_2O_5=moles\times {\text {Molar mass}}=0.05\times 284=14.2g[/tex]
Thus the theoretical yield of [tex]P_2O_5[/tex] is 14.2 grams.
