Respuesta :
Explanation:
The given data is as follows.
Volume = 1 L, Concentration of Ca = 5 ppm or 5 mg/L
As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.
Hence, calculate molarity of calcium as follows.
Molarity of Ca = [tex]\frac{\text{given concentration}}{\text{molar mass}}[/tex]
= [tex]\frac{0.005 g/l}{40.078 g/mol}[/tex]
Molarity of Ca = [tex]1.25 \times 10^{-4} M[/tex]
Hence, molarity of [tex]CaCl_{2}[/tex] is [tex]1.25 \times 10^{-4} M[/tex]. Since, volume is same so, moles of calcium chloride will be [tex]1.25 \times 10^{-4} mol[/tex].
Thus, we can conclude that mass of [tex]CaCl_{2}[/tex] will be as follows.
[tex]1.25 \times 10^{-4} \times 110.984[/tex] (molar mass of [tex]CaCl_{2}[/tex] = 110.984 g/mol)
= 0.0138 g
Thus, we can conclude that mass of [tex]CaCl_{2}[/tex] is 0.0138 g.
