A ball is thrown horizontally with a speed of 15 m/s, from the top of a 6.0 m tall hill. How far from the point on the ground directly below the launch point does the ball strike the ground?

Respuesta :

Answer:16.59 m

Explanation:

Given

initial horizontal speed of ball(u)=15 m/s

Height of building =6 m

Consider vertical motion first

[tex]h=u_yt+\frac{1}{2}gt^2[/tex]

here initial vertical velocity is zero

[tex]6=0+\frac{1}{2}\times 9.81\times t^2[/tex]

[tex]t=\sqrt{\frac{12}{9.81}}=1.106 s[/tex]

Thus time taken will also be 1.106 s in horizontal motion

[tex]R_x=u_xt+\frac{1}{2}at^2[/tex]

here a=0

[tex]R_x=15\times 1.106=16.59 m[/tex]