Respuesta :
Answer:
r = 14.13 m
Explanation:
Given that,
Charge 1 = +0.0129 C
Charge 2 = -0.00707 C
The force between charges, F = 4110 N
We need to find the distance between charges. Let the distance be r. The force between two charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\4110=\dfrac{9\times 10^9\times 0.0129\times 0.00707}{r^2}\\\\r=\sqrt{\dfrac{9\times 10^9\times 0.0129\times 0.00707}{4110}} \\\\r=14.13\ m[/tex]
So, the distance between charges is equal to 14.13 m.
