Respuesta :

jorgezarate

Answer:

t=12600ns

Explanation:

We use the relation between distance and velocity to solve this problem:

d=v*t

d=3.8km=3.8*10^3m

v=3*10^8 m/s^2         light's speed

we solve to find t:

t=d/v=(3.8*10^3)/(3*10^8)=1.26*10^(-5)s=12600*10^(-9)s=12600ns

dsdrajlin

Answer:

1.27 × 10⁴ ns

Explanation:

Given data

  • Distance (d): 3.80 km = 3.80 × 10³ m
  • Speed of light (v): 3.00 × 10⁸ m/s

We can find the time (t) that it takes to the light to travel 3.80 km using the following expression.

v = d/t

t = d/v

t = (3.80 × 10³ m)/(3.00 × 10⁸ m/s)

t = 1.27 × 10⁻⁵ s

We know that 1 s = 10⁹ ns. Then,

1.27 × 10⁻⁵ s × (10⁹ ns/1s) = 1.27 × 10⁴ ns

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