Answer:
The resultant velocity of the airplane is 213.41 m/s.
Step-by-step explanation:
Given that,
Velocity of an airplane in east direction, [tex]v_1=210\ mph[/tex]
Velocity of wind from the north, [tex]v_2=38\ mph[/tex]
Let east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.
We need to find the resultant velocity of the airplane. Let v is the resultant velocity. It can be calculated as :
[tex]v=\sqrt{v_1^2+v_2^2}[/tex]
[tex]v=\sqrt{(210)^2+(38)^2}[/tex]
v = 213.41 m/s
So, the resultant velocity of the airplane is 213.41 m/s. Hence, this is the required solution.
