A 10.0cm3 volume of alcohol has a mass of 7.05g. [tex]0.705 \frac{g}{c m^{3}}[/tex] is the density
Answer: [tex]0.705 \frac{g}{c m^{3}}[/tex]
Explanation:
The ratio between the mass of a substance and its unit volume is referred as density.
[tex]\text {Density}=\frac{\text { mass }}{\text { volume }}=\frac{7.05 g}{10.0 \mathrm{cm}^{3}}=0.705 \frac{g}{\mathrm{cm}^{3}}[/tex] is the Answer
Note:
1000 g = 1 kg
100 cm = 1 m
When we used to transform the given values into S.I units, then
[tex]\text {Density}\left(\frac{k g}{m^{3}}\right)=\frac{\text {Mass}(k g)}{\text {Volume}\left(m^{3}\right)}[/tex]
Alcohol’s volume can be written as, [tex]10.0 c m^{3} = 10 \times 10^{-2} m^{3}[/tex]
Alcohol’s mass can denote as, [tex]7.05 g = 7.05 \times 10^{-3} \mathrm{kg}[/tex]
Then, [tex]\text { Density }\left(\frac{k g}{m^{8}}\right)=\frac{, 00705(k g)}{0.1\left(m^{3}\right)} = .0705 \frac{\mathrm{kg}}{\mathrm{m}^{\mathrm{s}}}[/tex]
