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The concentration of dye in Solution A is 20.422 M. A serial dilution is performed to make Solutions B and C. In the first dilution, 2 mL of Solution A is diluted with 12 mL water to make Solution B. Then, 2 mL of Solution B is then diluted with 1 mL of water to make Solution C. What is the concentration of dye in Solution C? Provide your response to three significant figures in units of molarity.

Respuesta :

Answer:

1.95 M

Explanation:

Considering

Moles of A = Moles of B

Or,

[tex]Molarity_{A}\times Volume_{A}=Molarity_{B}\times Volume_{B}[/tex]

Given  that:

[tex]Molarity_{A}=20.422\ M[/tex]

[tex]Volume_{A}=2\ mL[/tex]

[tex]Volume_{B}=2+12=14\ mL[/tex]

[tex]Molarity_{B}=?\ M[/tex]

So,  

[tex]20.422\times 2=Molarity_{B}\times 14[/tex]

Molarity of solution B = 2.92 M

Again Considering,

Moles of B = Moles of C

Or,

[tex]Molarity_{B}\times Volume_{B}=Molarity_{C}\times Volume_{C}[/tex]

Given  that:

[tex]Molarity_{B}=2.92\ M[/tex]

[tex]Volume_{B}=2\ mL[/tex]

[tex]Volume_{C}=2+1=3\ mL[/tex]

[tex]Molarity_{C}=?\ M[/tex]

So,  

[tex]2.92\times 2=Molarity_{C}\times 3[/tex]

Molarity of solution C = 1.95 M

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