Answer:
Explanation:
Let T1 be the tension in rope of length 3 m and T2 be the tension in the rope of length 5 m.
Mass = 5 kg
Resolve the components of T1 and T2 and maintain the equilibrium in vertical and in horizontal direction.
First take equilibrium in horizontal direction:
[tex]T_{1}Sin52+T_{2}Sin40 = 5\times 9.8[/tex]
0.788 T1 + 0.642 T2 = 49 .... (1)
Take the equilibrium in horizontal direction
[tex]-T_{1}Cos52+T_{2}Cos40 =0[/tex]
-0.62 T1 + 0.766 T2 = 0 .... (2)
By solving equation (1) and (2) we get
T2 = 30.26 N
T1 = 37.53 N