Respuesta :

carlosego

Answer: [tex]-\frac{2}{25}a^{3}x^{3}[/tex]

Step-by-step explanation:

1. The problem asked for the product of [tex]\frac{2}{5}a^{2}x[/tex] and [tex]-\frac{1}{5}x^{2}a[/tex], therefore, you must mutliply them, as you can see below:

2. According the exponents propertiess, when you have a multiplication of two powers that has the equal base, you must add the exponents. THerefore, you have the following result:

 [tex](\frac{2}{5}a^{2}x)(-\frac{1}{5}x^{2}a)=-\frac{2}{25}a^{3}x^{3}[/tex]

zainebamir540

Answer:

(2/5a²x)( -1/5x²a) = -2/25a³x³

Step-by-step explanation:

We have given two terms.

2/5a²x and -1/5x²a

We have to find product of given terms.

We use following formula to solve this.

yᵃyᵇ = yᵃ⁺ᵇ

The product is:

(2/5a²x)( -1/5x²a) =2/5a²x . -1/5x²a

Combining like terms, we have

(2/5a²x)( -1/5x²a) = (2/5)(-1/5)(a²a)(xx²)

(2/5a²x)( -1/5x²a) = (-2/25)(a²⁺¹)(x¹⁺²)

(2/5a²x)( -1/5x²a) =( -2/25)(a³)(x³)

(2/5a²x)( -1/5x²a) = -2/25a³x³

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