Answer:
[tex]\displaystyle \frac{d}{dt}[t^{\sqrt{11}}] = \sqrt{11}t^{\sqrt{11} - 1}[/tex]
General Formulas and Concepts:
Calculus
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y = t^{\sqrt{11}}[/tex]
Step 2: Differentiate
- Basic Power Rule: [tex]\displaystyle y' = \sqrt{11}t^{\sqrt{11} - 1}[/tex]
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
