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A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 5.80 ✕ 105 m/s2 for 9.60 ✕ 10−4 s. What is its muzzle velocity (in m/s) (that is, its final velocity)? (Enter the magnitude.)

Respuesta :

Answer:

Final velocity will be 556.8 m/sec

Explanation:

We have given the average rate of change of velocity that is [tex]a=5.8\times 10^5m/sec[/tex]

Time [tex]t=9.6\times 10^{-4}sec[/tex]

Initial velocity of bullet will be zero that is u=0

Now according to first law of motion

v=u+at, here v is final velocity, u is initial velocity and t is time

So [tex]v=0+5.8\times 10^5\times 9.6\times 10^{-4}=556.8m/sec[/tex]

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