Answer:
The area of square 2 is 130 units square
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of a square is
[tex]A=b^{2}[/tex]
where
b is the length side of the square
Let
b1 ----> the length side of square 1
b2 ----> the length side of square 2
b3 ----> the length side of square 3
Applying the Pythagoras Theorem
[tex]b1^{2}=b2^{2}+b3^{2}[/tex] -----> equation A
we have
[tex]A1=250\ units^2[/tex]
[tex]A3=120\ units^2[/tex]
Remember that
[tex]A=b^{2}[/tex]
so
[tex]A1=b1^2=250\ units^2[/tex]
[tex]A3=b3^2=120\ units^2[/tex]
substitute in the equation A and solve for b2^2
[tex]250=b2^{2}+120[/tex]
[tex]b2^{2}=250-120[/tex]
[tex]b2^{2}=130[/tex]
[tex]A2=b2^{2}[/tex]
therefore
The area of square 2 is 130 units square
