Answer:
17.81 rad/s²
Explanation:
Distance = 76 m = s
Time taken = 6.3 s
Diameter of tire = 43 cm = 0.43 m
Radius of wheel = 43/2 = 21.5 cm = 0.215 m
Acceleration
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 76=0+\frac{1}{2}a6.3^2\\\Rightarrow a=76\times 2\frac{1}{6.3^2}[/tex]
Angular acceleration
[tex]\alpha=\frac{a}{R}\\\Rightarrow \alpha=\frac{76\times 2\frac{1}{6.3^2}}{0.215}\\\Rightarrow \alpha=17.81\ rad/s^2[/tex]
∴ Angular acceleration of the wheel is 17.81 rad/s²
