Scientists isolate cells in various phases of the cell cycle. They isolate a group of cells that have 1 1/2 times more DNA than G1 phase cells. What is the most likely part of the cell cycle from which these cells were isolated?

The process of formation of the daughter cell by the division of parent cells is known as cell division. Two main types of the cell division are mitosis and meiosis.

The different phase of cell cycle are G1 phase, S phase, G2 phase and M phase. The isolated cells have 1 1/2 times more DNA than G1 phase cells, this indicates the S phase or synthesis phase in which the amount of DNA has been synthesized.

Thus, the answer is S phase.

Oseni Oseni · Answer 2 · 2021-10-22T23:25:22+02:00

The most likely part of the cell cycle from which the cells with 11/2 more DNA than cells in G1 phase were isolated would be the S phase.

Generally, the cell cycle has 2 main phases:

The m phase or the mitotic phase during which cells actively divide
The interphase during which the cell makes some preparations for active division.

The interphase, in chronological order, include:

G1 phase: a period of cell's growth and development
S phase: a period of DNA replication/synthesis
G2 phase: a period of protein synthesis

At the end of the S phase, the amount of DNA in a cell before entering the S phase doubles. Thus, a cell in the S phase would be at the middle of DNA replication and, therefore, have more DNA amount than the same cell at G1 stage.

More on the cell cycle can be found here: https://brainly.com/question/12277305