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For electric forces we say that "likes repel, unlikes attract," but for the magnetic forces between two parallel current-carrying wires, we can say "likes attract, unlikes repel." To get a feel for the size of the effects, calculate the magnitude of the force per meter (that is, the force on one meter of wire) if I1= I2 = 12 amperes, and the distance between the wires is d = 4 centimeter.

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skyluke89

Answer:

[tex]7.2\cdot 10^{-4} N/m[/tex]

Explanation:

The magnetic force between two current-carrying wires is given by:

[tex]\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi r}[/tex]

where

[tex]\mu_0[/tex] is the vacuum permeability

I1 and I2 are the two currents

r is the distance between the wires

Here we have:

[tex]I_1 = I_2 = 12 A\\r = 4 cm = 0.04 m[/tex]

Substituting into the equation,

[tex]\frac{F}{L}=\frac{(4\pi \cdot 10^{-7})(12)(12)}{2\pi (0.04)}=7.2\cdot 10^{-4} N/m[/tex]

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