How do you graph this and know if it is continuous or not?

I'm going to plug in 2 for x: y=2-4=-2. So this one line is going to contain an open circle at (2,-2). I say open circle because we did not have that we could actually include x=2 here because it says for x less than 2.

Now we are going to enter in one more number less than 2....your choice.

Let's go with x=0. When you plug in 0 for x into y=x-4 you get y=0-4=-4. So our line is going to include (0,-4).

So we are going to graph the points (0,-4) and (2,-2) again where (2,-2) is an open circle. Connect these points. You may extend your line left because we have x<2, but do not extend it right of x=2.

Let's look at the other piece now: y=-2x+2 for x=2 or x>2.

I'm going to plug in 2 for x: y=-2(2)+2=-4+2=-2 so we are going to include the point (2,-2) on our line. This was actually a point we used from above that we didn't want to include. We do now want to include because of the x=2 in our inequality so the dot can now be filled in. We need one more point to graph this line. Let's plug in a number greater than 2 since our inequality say x=2 or x>2. You choose. How about x=3?

y=-2(3)+2=-6+2=-3. So we are going to include the point (3,-3). So starting at (2,-2) and going right to connect it to (3,-3), you could extend passed the (3,-3) to the right.

I will show you my graph.

There are no breaks in the "curve", so it is continuous for all real numbers.