Answer:
The molar concentration of [tex]35[/tex] g fructose in [tex]330 ml[/tex] solution is [tex]0.589[/tex]moles/litre
Explanation:
Given -
Molecular weight of fructose [tex]= 180 \frac{g}{mole}[/tex]
Can of coka coal has fructose [tex]= 35[/tex] gram
Volume of can of coke [tex]= 330[/tex] ml
Number of moles in [tex]35[/tex] grams of Fructose
[tex] = \frac{35}{180} \\= 0.194[/tex]
Molar concentration
[tex] = \frac{0.194}{0.33l} \\= 0.589\\[/tex] moles/litre
Hence, the molar concentration of [tex]35[/tex] g fructose in [tex]330 ml[/tex] solution is [tex]0.589[/tex]moles/litre
