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A baseball leaves a bat with a horizontal velocity of 20.0 m/s. When it has left the bat for a time of 0.250 s (Assume air resistance is negligible). How far will it have moved horizontally?

Respuesta :

Answer:

The distance is 5 m.

Explanation:

Given that,

Horizontal velocity = 20.0 m/s

Time t = 0.250 s

We need to calculate the horizontal distance

The distance traveled by the baseball with horizontal velocity in time t is given by

Using formula for horizontal distance

[tex]d = v\times t[/tex]

[tex]d = 20.0\times0.250[/tex]

[tex]d=5\ m[/tex]

Hence, The distance is 5 m.

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