Answer:
T = 259.2 C
Explanation:
In thermal expansion exercises, the equation is
ΔL = α L₀ ΔT
this equation is for one dimension, in the case of a volumetric body the equation changes to
ΔV = 3α V₀ ΔT
because the expansion is small
indicate that ΔV =V- V₀, the initial volume of V₀ = 50 cm³
ΔV = 0.425 cm³
ΔT = ΔV / (3α V₀)
ΔT = 0,425 / (50 3 12.1 10-6)
ΔT = 2,342 10² C
if we assume that initially the block is at room temperature To = 25C
the final temperature is
ΔT = T- To
T = ΔT + To
T = 234.2+ 25
T = 259.2 C
