Answer:
[tex]\dfrac{5}{36}[/tex]
Step-by-step explanation:
When tossing two number cubes, Leon can get such sample space
[tex]\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\\\end{array}[/tex]
There are 36 possible outcomes. Only (1,5), (2,4), (3,3), (4,2), (5,1) gives the sum of 6.
Hence, the probability that Leon will toss a sum of 6 is
[tex]\dfrac{5}{36}[/tex]
The probability that Leon will toss a sum of 6 is;
P(that Leon will toss a sum of 6) = 5/36
A cube here is same as a dice.
Now, a dice has 6 faces numbered from 1 to 6.
Now,we want to find the probability of tossing a sum of 6.
When we have 2 dices, the possible number of sums we can have are 36 total possible outcomes.
Now, the number of outcomes out of the 36 that can sum up to 6 are;
(1, 5), (2, 4), (3, 3), (5, 1) and (4, 2).
Thus, there are 5 possible sums that can be 6.
Therefore;
P(that Leon will toss a sum of 6) = 5/36
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