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how much energy is required to melt 2.5 moles of ice as 0.0 degrees Celsius to liquid water at 0.0 degrees Celsius ​

Respuesta :

MathPhys

Answer:

15 kJ

Explanation:

The latent heat of water at 0°C is 334 J/g.

1 mole of water is 18 g.

m = 2.5 mol × 18 g/mol

m = 45 g

q = mL

q = (45 g) (334 J/g)

q ≈ 15,000 J

It takes about 15 kJ.

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