For this case we have that by definition:
[tex]Secant (A) = \frac {1} {Cosine (A)}[/tex]
Then, we find the cosine of the angle H, this will be given by the leg adjacent to H on the hypotenuse of the triangle.
[tex]Cos (H) = \frac {g} {f}[/tex]
So, the secant of H is given by:[tex]Sec {H} = \frac {1} {\frac {g} {f}}\\Sec {H} = \frac {f} {g}[/tex]
Answer:
Option C
