A plane passes over point a with a velocity of 5000 m/s north. Sixty seconds later it passes over point b at a velocity of 10,000 m/s north. What is the plane’s acceleration from A to B?

Respuesta :

Answer:

The plane’s acceleration from A to B is

[tex]a =83.33\ m/s^2[/tex]

Explanation:

The acceleration of an object is a measure of how its speed changes over time.

In this case, we know that the plane initially has a velocity of 5000 m/s when it passes through point A, and when it passes through point B, 60 seconds later it has a velocity of 10,000 m/s.

Then the average acceleration is calculated as

[tex]a =\frac{s_2-s_1}{t_2-t_1}[/tex]

Where

[tex]s_2 = 10 000[/tex] is the final speed

[tex]s_1=5000[/tex] is the initial velocity

[tex]t_2 -t_1=60[/tex] is the time it took for the object to reach the final speed

Then

[tex]a =\frac{10000-5000}{60}[/tex]

[tex]a =\frac{5000}{60}[/tex]

[tex]a =83.33\ m/s^2[/tex]